81. Potassium nitrate is not used :

Potassium nitrate is not used :

[amp_mcq option1=”as a fertilizer” option2=”in medicine” option3=”in making gunpowder” option4=”as a preservative of meat products” correct=”option2″]

This question was previously asked in
UPSC CDS-2 – 2024
Potassium nitrate (KNO3), also known as saltpeter or nitre, has several common uses. It is widely used as a fertilizer (source of potassium and nitrogen), as an oxidizing agent in black powder (gunpowder), and as a food additive (E252) for curing meat products. While potassium nitrate has historical medicinal mentions (e.g., as a diuretic), it is not commonly used as a primary medicine in modern pharmaceutical practice compared to its industrial and food preservation roles.
– Potassium nitrate is a source of potassium and nitrogen for plants.
– It is a strong oxidizing agent used in explosives.
– It acts as a preservative and curing agent in meat.
Modern medicine primarily relies on different compounds for the roles potentially associated with potassium nitrate historically. Its uses in fertilizer, gunpowder, and food preservation are well-established and current.

82. What is the total number of naturally occurring elements ?

What is the total number of naturally occurring elements ?

[amp_mcq option1=”114″ option2=”94″ option3=”86″ option4=”82″ correct=”option2″]

This question was previously asked in
UPSC CDS-2 – 2023
Naturally occurring elements are those found on Earth. This typically includes elements that exist in substantial quantities as well as those found in trace amounts resulting from natural decay processes.
Elements up to atomic number 92 (Uranium) are generally considered naturally occurring on Earth in macroscopic quantities. Elements with atomic numbers 93 (Neptunium) and 94 (Plutonium) also occur naturally, but only in trace amounts, primarily as products of neutron capture and radioactive decay of Uranium. Elements beyond 94 are predominantly synthetic, created in laboratories or nuclear reactions, although some very heavy elements might exist fleetingly in specific astrophysical events.
Based on the common understanding and options provided, the number of naturally occurring elements including those in trace amounts is considered to be 94 (up to Plutonium). Some definitions might limit it to 92 (up to Uranium) if excluding elements only found from decay chains or in trace quantities. However, 94 is the most appropriate choice among the given options.

83. Which one among the following substances is a compound ?

Which one among the following substances is a compound ?

[amp_mcq option1=”Sugar” option2=”Air” option3=”Milk” option4=”Tea” correct=”option1″]

This question was previously asked in
UPSC CDS-2 – 2023
A compound is a substance formed when two or more different elements are chemically bonded together in a fixed ratio. A mixture is a substance composed of two or more components physically mixed, where each component retains its individual properties and the composition can vary.
Sugar (commonly sucrose, C₁₂H₂₂O₁₁) is made up of Carbon, Hydrogen, and Oxygen atoms chemically combined in a fixed ratio. Therefore, sugar is a compound. Air is a mixture of gases like nitrogen, oxygen, argon, carbon dioxide, etc. Milk is a complex mixture of water, fats, proteins, carbohydrates, minerals, etc. Tea is an aqueous mixture containing compounds extracted from tea leaves.
Elements are pure substances consisting only of atoms that all have the same number of protons in their atomic nuclei. Compounds can be broken down into simpler substances (elements) by chemical means, while mixtures can be separated into their components by physical means.

84. Which one of the following equations is the balanced chemical equation

Which one of the following equations is the balanced chemical equation for the given reaction ?
$\text{Fe + H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4\text{ + H}_2$

[amp_mcq option1=”$\text{Fe + 4H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4\text{ + H}_2$” option2=”$\text{3Fe + H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4\text{ + 2H}_2$” option3=”$\text{3Fe + 4H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4\text{ + 4H}_2$” option4=”$\text{3Fe + 4H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4\text{ + H}_2$” correct=”option3″]

This question was previously asked in
UPSC CDS-2 – 2023
A balanced chemical equation must have the same number of atoms of each element on both the reactant side and the product side. The given unbalanced equation is Fe + H2O $\rightarrow$ Fe3O4 + H2. To balance this equation, we can follow these steps:
1. Balance Fe: There are 3 Fe atoms on the right (in Fe3O4) and 1 on the left. Multiply Fe on the left by 3: 3Fe + H2O $\rightarrow$ Fe3O4 + H2.
2. Balance O: There are 4 O atoms on the right (in Fe3O4) and 1 on the left (in H2O). Multiply H2O on the left by 4: 3Fe + 4H2O $\rightarrow$ Fe3O4 + H2.
3. Balance H: Now there are 4 * 2 = 8 H atoms on the left. There are 2 H atoms on the right (in H2). Multiply H2 on the right by 4: 3Fe + 4H2O $\rightarrow$ Fe3O4 + 4H2.
Checking the balanced equation:
Left side: Fe = 3, H = 4 * 2 = 8, O = 4 * 1 = 4
Right side: Fe = 3, H = 4 * 2 = 8, O = 4
The number of atoms of each element is equal on both sides.
Balancing chemical equations adheres to the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction. Option C is the only option that shows the coefficients 3, 4, 1, and 4 respectively, which correctly balance the atoms on both sides of the equation.

85. Which one of the following materials is present in a guard tube (dryin

Which one of the following materials is present in a guard tube (drying tube) that is used for preparation of HCl gas?

[amp_mcq option1=”Calcium chloride” option2=”Calcium bromide” option3=”Calcium iodide” option4=”Calcium fluoride” correct=”option1″]

This question was previously asked in
UPSC CDS-2 – 2021

Calcium chloride is commonly used as a drying agent in guard tubes (drying tubes) during the preparation of dry HCl gas.

Hydrogen chloride (HCl) gas is acidic and reacts with basic drying agents like quicklime (CaO) or NaOH. Therefore, an acidic or neutral drying agent is required. Anhydrous calcium chloride (CaCl2) is a neutral salt and a highly efficient drying agent that does not react with HCl gas.

Concentrated sulfuric acid is another common drying agent for HCl, but calcium chloride is often used in solid form in drying tubes. Other calcium halides like calcium bromide, iodide, and fluoride are less commonly used or less effective as drying agents for general laboratory purposes compared to calcium chloride.

86. Lead nitrate on heating gives

Lead nitrate on heating gives

[amp_mcq option1=”PbO₂ and NO₂” option2=”PbO and NO₂” option3=”PbO and NO” option4=”PbO₂ and NO” correct=”option2″]

This question was previously asked in
UPSC CDS-2 – 2020
Heating lead nitrate (Pb(NO₃)₂) causes thermal decomposition, producing lead(II) oxide (PbO), nitrogen dioxide (NO₂), and oxygen (O₂).
The balanced chemical equation for the thermal decomposition of lead nitrate is: 2 Pb(NO₃)₂(s) → 2 PbO(s) + 4 NO₂(g) + O₂(g). Nitrogen dioxide is a reddish-brown gas, and this decomposition is often demonstrated to show its production.
The specific oxide formed depends on the metal and the temperature of decomposition. For lead nitrate, the primary solid product is lead(II) oxide (PbO). Lead(IV) oxide (PbO₂) is not formed under these conditions as a primary product of lead nitrate decomposition.

87. Identify the correct pair of elements among the following which are li

Identify the correct pair of elements among the following which are liquid at room temperature and standard pressure.

[amp_mcq option1=”Bromine and fluorine” option2=”Mercury and rubidium” option3=”Bromine and thallium” option4=”Bromine and mercury” correct=”option4″]

This question was previously asked in
UPSC CDS-2 – 2020
At room temperature (typically 20-25°C) and standard pressure (1 atm), only two elements are liquid: Bromine (Br₂) and Mercury (Hg). Bromine is a reddish-brown volatile liquid that exists as diatomic molecules (Br₂). Mercury is a silvery-white heavy metal.
Bromine and Mercury are the only two elements that exist as liquids under standard conditions of temperature and pressure.
Fluorine (F₂) is a pale yellow gas at room temperature. Rubidium (Rb) is an alkali metal that is solid at room temperature but has a low melting point (39.3 °C). Thallium (Tl) is a metal that is solid at room temperature. Some other elements like Gallium (Ga), Cesium (Cs), and Francium (Fr) melt at temperatures slightly above typical room temperature but are often considered liquids at slightly elevated room temperatures or in warm environments. However, only Bromine and Mercury are liquid under *standard* room temperature conditions.

88. A mixture of sodium chloride (salt) and ammonium chloride can be separ

A mixture of sodium chloride (salt) and ammonium chloride can be separated by

[amp_mcq option1=”sublimation” option2=”filtration” option3=”chromatography” option4=”distillation” correct=”option1″]

This question was previously asked in
UPSC CDS-2 – 2020
A mixture of sodium chloride (NaCl) and ammonium chloride (NH₄Cl) can be separated by sublimation. Ammonium chloride is a compound that sublimes upon heating, meaning it transitions directly from a solid to a gas without passing through a liquid phase. Sodium chloride, on the other hand, is a stable ionic compound that does not sublime under normal heating conditions; it melts at a high temperature. By heating the mixture, the ammonium chloride vaporizes and can be collected on a cool surface, separating it from the solid sodium chloride residue.
Sublimation is a process used to separate mixtures where one component sublimes and the other does not.
Filtration is used to separate insoluble solids from liquids. Chromatography is used for separating components of a mixture based on their differential partitioning between a stationary and a mobile phase. Distillation is used to separate liquids with different boiling points or to separate liquids from non-volatile solids. None of these methods are suitable for separating solid NaCl from solid NH₄Cl based on their physical properties in this context.

89. Which one of the following types of glasses is used for making optical

Which one of the following types of glasses is used for making optical instruments?

[amp_mcq option1=”Pyrex glass” option2=”Soft glass” option3=”Hard glass” option4=”Flint glass” correct=”option4″]

This question was previously asked in
UPSC CDS-2 – 2017
The correct option is D) Flint glass.
Flint glass is a type of optical glass characterized by a high refractive index and relatively high dispersion. It is often used in combination with crown glass (lower refractive index, lower dispersion) to make achromatic lenses that reduce chromatic aberration (the distortion caused by the different wavelengths of light being refracted at slightly different angles). These properties are crucial for the performance of optical instruments like cameras, telescopes, and microscopes.
Pyrex glass is a borosilicate glass known for its thermal shock resistance and is used for laboratory glassware and cookware. Soft glass (soda-lime glass) is common glass used for windows and containers. Hard glass generally refers to types like borosilicate glass with high softening points but isn’t a specific category used for optical purposes like flint glass.

90. Pearl is a hard object produced within the soft tissues of a mollusk.

Pearl is a hard object produced within the soft tissues of a mollusk. Which one of the following is the main constituent of pearl?

[amp_mcq option1=”Calcium carbonate” option2=”Calcium oxide” option3=”Calcium nitrate” option4=”Calcium sulphate” correct=”option1″]

This question was previously asked in
UPSC CDS-2 – 2017
The main constituent of pearl is calcium carbonate.
Pearls are formed within mollusks when an irritant, such as a parasite or a piece of shell, enters the shell. The mollusk secretes layers of nacre (mother-of-pearl) around the irritant as a defense mechanism. Nacre is composed primarily of microscopic crystals of calcium carbonate (CaCO3), mainly in the aragonite form, cemented together by an organic protein matrix called conchiolin.
The calcium carbonate layers combined with the organic matrix create the iridescent luster characteristic of pearls. The quality and value of a pearl depend on factors like size, shape, color, luster, surface quality, and nacre thickness.

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