If the work done on the system or by the system is zero, which one of the following statements for a gas kept at a certain temperature is correct ?
[amp_mcq option1=”Change in internal energy of the system is equal to flow of heat in or out of the system.” option2=”Change in internal energy of the system is less than heat transferred.” option3=”Change in internal energy of the system is more than the heat flow.” option4=”Cannot be determined.” correct=”option1″]
This question was previously asked in
UPSC NDA-2 – 2019
The first law of thermodynamics states that the change in internal energy of a system ($\Delta U$) is equal to the heat added to the system ($Q$) minus the work done by the system ($W$). This can be written as $\Delta U = Q – W$. The question states that the work done on the system or by the system is zero, meaning $W = 0$. Substituting this into the first law equation gives $\Delta U = Q – 0$, which simplifies to $\Delta U = Q$. Therefore, the change in internal energy of the system is equal to the flow of heat in or out of the system.
– First Law of Thermodynamics: $\Delta U = Q – W$.
– Work done is zero ($W=0$).
– The change in internal energy is directly equal to the heat transfer when no work is done.