31. Which one of the following elements forms compounds with pronounced co

Which one of the following elements forms compounds with pronounced covalent character?

Lithium (Li)
Sodium (Na)
Potassium (K)
Rubidium (Rb)
This question was previously asked in
UPSC CISF-AC-EXE – 2019
Lithium (Li) forms compounds with the most pronounced covalent character among the given options.
The formation of covalent character in predominantly ionic compounds is explained by Fajans’ Rules. These rules state that a compound is more likely to have covalent character if:
1. The cation is small.
2. The cation has a high charge (not applicable here as all form +1 ions).
3. The anion is large (not directly comparable here as the anion is not specified, but assume it’s a common one like a halide).
4. The cation has a pseudo noble gas configuration (not applicable here as alkali metals form noble gas configuration ions).

The given elements are alkali metals: Lithium (Li), Sodium (Na), Potassium (K), and Rubidium (Rb). When they form compounds, they form +1 ions: Li⁺, Na⁺, K⁺, Rb⁺.
Their ionic radii increase down the group: Li⁺ < Na⁺ < K⁺ < Rb⁺. According to Fajans' Rules, smaller cations have higher polarizing power (the ability to distort the electron cloud of the anion), which leads to increased covalent character in the bond. Li⁺ is the smallest cation among Li⁺, Na⁺, K⁺, and Rb⁺. Therefore, Li⁺ has the highest polarizing power and forms compounds with anions that exhibit the most pronounced covalent character compared to the compounds of Na, K, and Rb with the same anion. For example, LiCl has significantly more covalent character than NaCl, KCl, or RbCl.

Lithium exhibits several properties that are anomalous compared to the other alkali metals, often showing similarities to magnesium (diagonal relationship). This pronounced covalent character is one such anomaly, explaining why compounds like LiCl are soluble in organic solvents and why Li₂CO₃ is less stable to heat than other alkali metal carbonates.

32. Two reactants in a flask produce bubbles of gas that turn limewater mi

Two reactants in a flask produce bubbles of gas that turn limewater milky. The gas is

SO₂
NO₂
CO
CO₂
This question was previously asked in
UPSC CISF-AC-EXE – 2019
The gas that turns limewater milky is CO₂.
Limewater is a dilute aqueous solution of calcium hydroxide, Ca(OH)₂. It is a common test reagent for carbon dioxide (CO₂).
When carbon dioxide gas is bubbled through limewater, it reacts with calcium hydroxide to form a precipitate of calcium carbonate (CaCO₃), which is insoluble in water and makes the solution appear milky or cloudy.
The chemical reaction is:
Ca(OH)₂(aq) + CO₂(g) → CaCO₃(s) + H₂O(l)

If excess carbon dioxide is bubbled through the milky solution, the calcium carbonate precipitate reacts further to form soluble calcium bicarbonate, Ca(HCO₃)₂, and the milky appearance disappears.
CaCO₃(s) + CO₂(g) + H₂O(l) → Ca(HCO₃)₂(aq)

Other gases listed:
– SO₂ (Sulfur dioxide) also reacts with limewater, but forms calcium sulfite (CaSO₃), which is also insoluble and causes turbidity. However, the reaction with CO₂ is the most common and characteristic test for CO₂.
– NO₂ (Nitrogen dioxide) is an acidic gas and would react with Ca(OH)₂, but it typically doesn’t produce a milky precipitate with limewater as characteristically as CO₂.
– CO (Carbon monoxide) is a neutral gas and does not react with limewater.

Given the standard chemical tests, turning limewater milky is the definitive test for CO₂.

This reaction is commonly used in experiments to detect the production of carbon dioxide, such as in respiration or combustion.

33. Which one of the following elements has the oxidation state as +7 ?

Which one of the following elements has the oxidation state as +7 ?

Nitrogen
Phosphorus
Manganese
Magnesium
This question was previously asked in
UPSC CISF-AC-EXE – 2018
The correct answer is Manganese.
Manganese (Mn) is a transition metal that can exhibit various oxidation states, including +2, +3, +4, +6, and +7. In compounds like potassium permanganate (KMnO4), Manganese has an oxidation state of +7.
Nitrogen typically exhibits oxidation states ranging from -3 to +5 (e.g., +5 in HNO3 or N2O5). Phosphorus typically exhibits oxidation states of -3, +3, and +5 (e.g., +5 in H3PO4 or P4O10). Magnesium is an alkaline earth metal and almost exclusively exhibits an oxidation state of +2 in its compounds. Therefore, among the given options, only Manganese can have an oxidation state of +7.

34. Graphite is a good conductor of electricity. It is because of its

Graphite is a good conductor of electricity. It is because of its

linear structure
tetrahedral structure
triangular planar structure
hexagonal multilayer structure
This question was previously asked in
UPSC CISF-AC-EXE – 2018
Graphite is a good conductor of electricity because of its structure. It consists of layers of carbon atoms arranged in a hexagonal lattice. Within each layer, carbon atoms are bonded covalently, with each carbon atom bonded to three others. This $sp^2$ hybridization leaves one unhybridized p-orbital per carbon atom, which overlaps with adjacent p-orbitals to form a delocalized pi electron system across the entire layer. These delocalized electrons are mobile and can carry electric charge, making the layers conductive. The overall structure is described as hexagonal multilayer, which creates the environment for these delocalized electrons.
The electrical conductivity of graphite is due to the presence of delocalized electrons in its layered hexagonal structure.
The layers in graphite are weakly bonded by Van der Waals forces, allowing them to slide easily, which is why graphite is soft and used as a lubricant. This contrasts with diamond, which has a rigid tetrahedral structure with all valence electrons localized in sigma bonds, making it an electrical insulator.

35. An acid solution of pH equal to three is gradually diluted with water.

An acid solution of pH equal to three is gradually diluted with water. As a result of this dilution, the pH of the solution will

reach near to zero.
reach near to fourteen.
reach near to seven.
remain unchanged.
This question was previously asked in
UPSC CISF-AC-EXE – 2018
An acid solution with pH = 3 has a relatively high concentration of H+ ions. Diluting this solution with pure water (which has a neutral pH of 7) reduces the concentration of the acid, and thus the concentration of H+ ions from the acid. The total concentration of H+ ions approaches the concentration of H+ ions in pure water (which is $10^{-7}$ M at 25°C, corresponding to pH 7). As the concentration of H+ decreases, the pH value (which is -log[H+]) increases. The pH will move from 3 towards 7, but it will not exceed 7 when diluting with pure water.
Diluting an acidic solution with neutral water increases its pH, moving it towards 7.
Similarly, diluting a basic solution with neutral water decreases its pH, moving it towards 7. The pH of a solution being diluted with pure water will approach the pH of pure water (7), but will not cross the neutrality point unless the original solution was extremely concentrated or involved complex acid-base equilibria not typical for this type of question.

36. What is a fire triangle ?

What is a fire triangle ?

Combination of Oxygen, Fuel and Heat
Combination of Heat, Gas and CO₂
Combination of Fuel, CO₂ and Heat
None of the above
This question was previously asked in
UPSC CISF-AC-EXE – 2017
The correct answer is A) Combination of Oxygen, Fuel and Heat.
The fire triangle is a simple model illustrating the three elements necessary for most fires to ignite and continue to burn: Fuel (something to burn), Oxygen (a supply of oxidizer, usually air), and Heat (sufficient to raise the fuel to its ignition temperature). Removing any one of these elements can extinguish the fire.
A more complex model, the fire tetrahedron, adds a fourth element: a chemical chain reaction. This is particularly relevant for understanding how certain extinguishing agents (like halons) work by interrupting this reaction. However, the fundamental fire triangle remains a widely used and accurate model for basic understanding.

37. In case of fire due to electric short circuit, which one of the follow

In case of fire due to electric short circuit, which one of the following types of fire extinguishers is used ?

Foam extinguisher
Dry chemical powder extinguisher
Pressurized water extinguisher
None of the above
This question was previously asked in
UPSC CISF-AC-EXE – 2017
The correct answer is B) Dry chemical powder extinguisher.
Fires involving electrical equipment (often classified as Class E or Class C fires) require an extinguishing agent that is non-conductive. Water-based extinguishers (like pressurized water or foam, which is largely water) are conductive and can pose a severe electrocution risk to the user when used on electrical fires. Dry chemical powder extinguishers (like ABC powder) use fine powder that smothers the fire and also works on Class A, B, and C fires, making them suitable and common for electrical fires.
Other suitable extinguishing agents for electrical fires include Carbon Dioxide (CO₂) extinguishers and Halon or Halocarbon agents (though some are restricted due to environmental concerns). The classification of fires (A, B, C, D, K, or E) helps determine the appropriate extinguishing agent. Electrical fires are commonly referred to as Class C in the US and Class E in Europe/Australia, referring to energized electrical equipment.

38. Which one of the following materials is not present in gun powder?

Which one of the following materials is not present in gun powder?

Sulphur
Charcoal
Potassium nitrate
Barium sulphate
This question was previously asked in
UPSC CISF-AC-EXE – 2017
Barium sulphate is not present in traditional gunpowder.
Traditional black gunpowder consists of a mixture of three main components: Potassium nitrate (KNO₃), Charcoal (primarily carbon), and Sulphur (S).
Potassium nitrate acts as the oxidizer, providing oxygen for the rapid combustion of the fuel components, charcoal and sulphur. Sulphur also helps to stabilize the mixture and lowers the ignition temperature. Barium sulphate is sometimes used in pyrotechnics to produce a green color, but it is not a standard ingredient in black gunpowder propellant.

39. Which one of the following statements about carbon dioxide is not

Which one of the following statements about carbon dioxide is not correct?

It is a basic oxide.
It is a greenhouse gas.
It forms dry ice.
It is consumed during photosynthesis.
This question was previously asked in
UPSC CISF-AC-EXE – 2017
The statement that carbon dioxide is a basic oxide is not correct.
Oxides of non-metals, like carbon dioxide (CO₂), are typically acidic oxides. When dissolved in water, CO₂ forms carbonic acid (H₂CO₃). Basic oxides are usually formed by metals.
Carbon dioxide is indeed a significant greenhouse gas, trapping heat in the atmosphere. Solid carbon dioxide is commonly known as dry ice. During photosynthesis, plants consume carbon dioxide from the atmosphere, along with water and sunlight, to produce glucose (sugar) and oxygen.

40. Which one of the following is a reducing substance?

Which one of the following is a reducing substance?

Oxygen
Iron
Potassium permanganate
Potassium dichromate
This question was previously asked in
UPSC CISF-AC-EXE – 2017
Iron is a reducing substance.
A reducing substance (or reductant) is a species that loses electrons in a redox reaction, causing another substance to be reduced while itself being oxidized. Iron can readily lose electrons to form Fe²⁺ or Fe³⁺ ions, thus acting as a reducing agent.
Oxygen, Potassium permanganate (KMnO₄), and Potassium dichromate (K₂Cr₂O₇) are typically strong oxidizing agents, meaning they readily gain electrons from other substances, causing the other substance to be oxidized while they themselves are reduced.

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