The molecular mass of sulphuric acid is 98. If 49 g of the acid is dissolved in water to make one litre of solution, what will be the strength of the acid?
[amp_mcq option1=”Two normal” option2=”One normal” option3=”0·5 normal” option4=”Four normal” correct=”option2″]
This question was previously asked in
UPSC CDS-1 – 2017
The molecular mass of sulfuric acid (H₂SO₄) is 98 g/mol. 49 g of H₂SO₄ is dissolved in water to make 1 litre of solution.
Number of moles of H₂SO₄ = Mass / Molar mass = 49 g / 98 g/mol = 0.5 mol.
The molarity of the solution is Moles / Volume (L) = 0.5 mol / 1 L = 0.5 M.
Normality (N) is defined as Molarity (M) multiplied by the n-factor (equivalents per mole). For sulfuric acid acting as an acid, it has two acidic protons (H⁺) that can be donated, so its n-factor is 2.
Normality = Molarity × n-factor = 0.5 M × 2 = 1 N.
The strength of the acid solution is one normal.
Normality is a measure of concentration defined as the number of gram equivalents of solute per litre of solution. For acids, the gram equivalent weight is the molecular weight divided by the number of acidic protons per molecule.