The correct answer is: A. Velocity is maximum at its mean position.
In a simple harmonic motion, the velocity is maximum at the extreme positions and minimum at the mean position. The acceleration is maximum at the mean position and zero at the extreme positions.
The velocity of a particle in simple harmonic motion is given by:
$$v = \pm \omega \sqrt{A^2 – x^2}$$
where $\omega$ is the angular frequency of the motion, $A$ is the amplitude of the motion, and $x$ is the displacement of the particle from the mean position.
The acceleration of a particle in simple harmonic motion is given by:
$$a = -\omega^2 x$$
where $\omega$ is the angular frequency of the motion and $x$ is the displacement of the particle from the mean position.
From the equations for the velocity and acceleration, we can see that the velocity is maximum at the extreme positions, where $x = \pm A$, and minimum at the mean position, where $x = 0$. The acceleration is maximum at the mean position, where $x = 0$, and zero at the extreme positions, where $x = \pm A$.
Therefore, the statement “Velocity is maximum at its mean position” is incorrect.