[amp_mcq option1=”Hoop strain of the walls of a cylinder due to liquid is $$\frac{{{\text{pd}}}}{{2{\text{tE}}}}\left[ {1 – \frac{1}{{2{\text{m}}}}} \right]$$” option2=”Longitudinal strain in the walls of a cylinder due to liquid is $$\frac{{{\text{pd}}}}{{2{\text{tE}}}}\left[ {\frac{1}{2} – \frac{1}{{\text{m}}}} \right]$$” option3=”Volumetric change in the cylinder due to liquid is $$\frac{{{\text{pd}}}}{{2{\text{tE}}}}\left[ {\frac{5}{2} – \frac{2}{{\text{m}}}} \right]$$” option4=”All the above” correct=”option4″]
The correct answer is D. All the above.
The hoop strain of the walls of a cylinder due to liquid is given by:
$$\varepsilon_h = \frac{p d}{2 t E} \left[ 1 – \frac{1}{2 m} \right]$$
where:
- $p$ is the pressure of the liquid
- $d$ is the diameter of the cylinder
- $t$ is the thickness of the cylinder
- $E$ is the Young’s modulus of the material of the cylinder
- $m$ is the Poisson’s ratio of the material of the cylinder
The longitudinal strain in the walls of a cylinder due to liquid is given by:
$$\varepsilon_l = \frac{p d}{2 t E} \left[ \frac{1}{2} – \frac{1}{m} \right]$$
The volumetric change in the cylinder due to liquid is given by:
$$\Delta V = \frac{p d^2}{2 t E} \left[ \frac{5}{2} – \frac{2}{m} \right]$$
Therefore, all the statements in the question are correct.