Optically active 2-octanol rapidly loses its optical activity when exposed to A. dilute acid B. base C. light D. humidity

dilute acid
base
light
humidity

The correct answer is C. light.

Optically active 2-octanol is a chiral molecule, which means that it is not superimposable on its mirror image. This chirality is due to the presence of a chiral carbon atom, which is a carbon atom that is bonded to four different groups. When optically active 2-octanol is exposed to light, the chiral carbon atom can undergo a process called racemization, which is the process of converting a chiral molecule into a racemic mixture. A racemic mixture is a mixture of equal amounts of the two enantiomers of a chiral molecule. Enantiomers are molecules that are mirror images of each other but are not superimposable. When optically active 2-octanol is racemized, it loses its optical activity.

Dilute acid and base do not cause optically active 2-octanol to lose its optical activity. Humidity does not cause optically active 2-octanol to lose its optical activity.

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