Match List-I with List-II and select the correct answer using the code

Match List-I with List-II and select the correct answer using the code given below :

List-I (Process)List-II (Contaminant)
A. Aeration followed by filtration1. Removal of colour
B. Reverse Osmosis2. Removal of microorganism
C. Filtration through activated carbon3. Removal of iron
D. Treatment with UV light4. Removal of excess salts

Code:

3 1 4 2
4 3 2 1
3 4 1 2
2 4 1 3
This question was previously asked in
UPSC CAPF – 2009
The correct match between the water treatment processes and the contaminants removed is A-3, B-4, C-1, D-2.
– A. Aeration followed by filtration: Aeration oxidizes dissolved iron and manganese, forming precipitates that are then removed by filtration. Thus, it’s used for the removal of iron (3).
– B. Reverse Osmosis: This process uses a semipermeable membrane to remove dissolved salts and other impurities from water, effectively used for desalination or removal of excess salts (4).
– C. Filtration through activated carbon: Activated carbon is highly effective at adsorbing organic compounds, chlorine, and other substances that cause color, odor, and taste in water. Thus, it’s used for the removal of colour (1).
– D. Treatment with UV light: Ultraviolet (UV) light treatment is a disinfection method that inactivates microorganisms like bacteria and viruses by damaging their DNA. Thus, it’s used for the removal of microorganisms (2).
Matching the processes to the contaminants:
A. Aeration followed by filtration – 3. Removal of iron
B. Reverse Osmosis – 4. Removal of excess salts
C. Filtration through activated carbon – 1. Removal of colour
D. Treatment with UV light – 2. Removal of microorganism
This corresponds to the code 3 4 1 2, which is option C.