It is known that two roots of the non-linear equation x3 – 6×2 + 11x – 6 = 0 and 1 and 3. The third root will be A. \[{\rm{\hat j}}\] B. -j C. 2 D. 4

The correct answer is $\boxed{-2}$.

The sum of the roots of a polynomial equation is equal to the negative of the coefficient of the $x^2$ term divided by the coefficient of the $x^3$ term. In this case, the coefficient of the $x^2$ term is $-6$ and the coefficient of the $x^3$ term is $1$, so the sum of the roots is $-\frac{-6}{1} = 6$. We know that two of the roots are $1$ and $3$, so the third root must be $6-1-3 = \boxed{-2}$.

The other options are incorrect because they are not roots of the given equation.