In Repetition Code, how many information bit/s is/are present in addition to n-1 parity bits? A. One B. Two C. Four D. Eight

[amp_mcq option1=”One” option2=”Two” option3=”Four” option4=”Eight” correct=”option1″]

The correct answer is A. One.

In Repetition Code, each data bit is repeated n times, where n is the number of parity bits. This means that there is one information bit for every n parity bits.

For example, if we have a 3-bit data word 101, we would encode it as 11110101. In this case, there is one information bit (1) and three parity bits (111).

Repetition Code is a simple and effective error-correcting code. It can correct up to one bit error per codeword. However, it cannot correct multiple bit errors.

Here is a brief explanation of each option:

  • Option A: One. This is the correct answer. In Repetition Code, each data bit is repeated n times, where n is the number of parity bits. This means that there is one information bit for every n parity bits.
  • Option B: Two. This is incorrect. There is only one information bit per codeword in Repetition Code.
  • Option C: Four. This is incorrect. There is only one information bit per codeword in Repetition Code.
  • Option D: Eight. This is incorrect. There is only one information bit per codeword in Repetition Code.