The correct answer is A. 1.5.
The shape factor is a dimensionless parameter that is used to determine the plastic collapse load of a cross-section. It is defined as the ratio of the plastic moment of inertia of the cross-section to the yield moment of inertia of the cross-section.
For a triangular section, the shape factor is given by:
$S_f = \frac{I_p}{I_y} = \frac{bh^2}{6} \cdot \frac{6}{bh^2} = 1.5$
where $b$ is the width of the section, $h$ is the height of the section, and $I_p$ and $I_y$ are the plastic moment of inertia and the yield moment of inertia of the section, respectively.
The other options are incorrect because they do not represent the correct value of the shape factor for a triangular section.