In depletion mode pull-up, dissipation is high since current flows when? A. Vin = 1 B. Vin = 0 C. Vout = 1 D. Vout = 0

[amp_mcq option1=”Vin = 1″ option2=”Vin = 0″ option3=”Vout = 1″ option4=”Vout = 0″ correct=”option2″]

The correct answer is: B. Vin = 0.

In a depletion-mode MOSFET, the channel is initially depleted of charge carriers, so there is no current flow when a voltage is applied to the gate. However, when a voltage is applied to the gate that is greater than the threshold voltage, the channel becomes conductive and current flows. This current flow is what causes the dissipation in a depletion-mode pull-up.

In a depletion-mode pull-up, the MOSFET is connected in parallel with a resistor. When the input voltage (Vin) is high, the MOSFET is turned off and the resistor provides the only path for current to flow. This results in a small amount of dissipation. However, when the input voltage is low, the MOSFET is turned on and current flows through the MOSFET and the resistor. This results in a much larger amount of dissipation.

Therefore, the correct answer is: B. Vin = 0.

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