In a vacuum, a five-rupee coin, a feather of a sparrow bird and a mang

In a vacuum, a five-rupee coin, a feather of a sparrow bird and a mango are dropped simultaneously from the same height. The time taken by them to reach the bottom is t1, t2 and t3 respectively. In this situation, we will observe that

”t<sub>1</sub>
”t<sub>1</sub>
”t<sub>3</sub>
”t<sub>1</sub>
This question was previously asked in
UPSC NDA-2 – 2017
In a vacuum, there is no air resistance. According to the principles of physics, in the absence of air resistance, all objects dropped from the same height will fall with the same acceleration due to gravity, regardless of their mass, size, or shape. This means they will take the same amount of time to reach the ground. Therefore, the five-rupee coin, the feather, and the mango will all reach the bottom simultaneously, meaning $t_1 = t_2 = t_3$.
– In a vacuum, acceleration due to gravity is constant for all objects ($g$).
– Absence of air resistance.
– Time taken to fall from the same height is independent of mass.
This principle was first hypothesized by Galileo Galilei and later demonstrated convincingly in experiments, including the famous experiment conducted by astronaut David Scott on the Moon during the Apollo 15 mission, where a hammer and a feather were dropped simultaneously and hit the lunar surface at the same time. On Earth, air resistance significantly affects the fall time of objects, especially those with large surface area relative to mass like a feather.