In a lead-acid cell dilute sulfuric acid (electrolyte) approximately comprises the following

One part H2O, three parts H2SO4
Two parts H2O, two parts H2SO4
Three parts H2O, one part H2SO4
All H2SO4

The correct answer is: B. Two parts H2O, two parts H2SO4

A lead-acid battery is a type of rechargeable battery that uses lead electrodes and a sulfuric acid electrolyte. The electrolyte is a solution of sulfuric acid in water. The ratio of water to sulfuric acid in a lead-acid battery is typically 2:1. This means that for every two parts of water, there is one part of sulfuric acid.

The electrolyte in a lead-acid battery is important for several reasons. First, it provides the ions that are necessary for the battery to produce electricity. Second, it helps to cool the battery and prevent it from overheating. Third, it helps to prevent the electrodes from corroding.

The electrolyte in a lead-acid battery is a very important part of the battery. It is important to keep the electrolyte level in the battery at the correct level and to replace the electrolyte if it becomes too weak.

Here is a brief explanation of each option:

  • Option A: One part H2O, three parts H2SO4. This is not the correct ratio of water to sulfuric acid in a lead-acid battery. The correct ratio is 2:1.
  • Option B: Two parts H2O, two parts H2SO4. This is the correct ratio of water to sulfuric acid in a lead-acid battery.
  • Option C: Three parts H2O, one part H2SO4. This is not the correct ratio of water to sulfuric acid in a lead-acid battery. The correct ratio is 2:1.
  • Option D: All H2SO4. This is not the correct ratio of water to sulfuric acid in a lead-acid battery. The correct ratio is 2:1.
Exit mobile version