In a highly capacitive circuit the

Apparent power is equal to the actual power
Reactive power is more than the apparent power
Reactive power is more than the actual power
Actual power is more than its reactive power

The correct answer is: B. Reactive power is more than the apparent power.

In a highly capacitive circuit, the current leads the voltage by 90 degrees. This means that the reactive power is more than the apparent power. The reactive power is the product of the current and the voltage, but it is out of phase with the voltage. The apparent power is the product of the current and the voltage, but it is in phase with the voltage.

The following diagram shows the relationship between the current, voltage, and power in a highly capacitive circuit:

[Diagram of a highly capacitive circuit, showing the current leading the voltage by 90 degrees.]

The current is represented by the blue line, the voltage is represented by the red line, and the power is represented by the green line. The power is lagging the voltage by 90 degrees. This is because the reactive power is more than the apparent power.

The reactive power is the product of the current and the voltage, but it is out of phase with the voltage. The apparent power is the product of the current and the voltage, but it is in phase with the voltage.

In a highly capacitive circuit, the current leads the voltage by 90 degrees. This means that the reactive power is more than the apparent power.

Exit mobile version