If w is the specific weight of liquid and k the depth of any point from the surface, then pressure intensity at that point will be A. h B. wh C. $$\frac{{\text{w}}}{{\text{h}}}$$ D. $$\frac{{\text{h}}}{{\text{w}}}$$

[amp_mcq option1=”h” option2=”wh” option3=”$$\frac{{\text{w}}}{{\text{h}}}$$” option4=”$$\frac{{\text{h}}}{{\text{w}}}$$” correct=”option3″]

The correct answer is: $\boxed{\text{B}. wh}$.

The pressure intensity at a point in a fluid is given by the following equation:

$$P = \rho g h$$

where:

• $P$ is the pressure intensity,
• $\rho$ is the density of the fluid,
• $g$ is the acceleration due to gravity, and
• $h$ is the depth of the point from the surface.

The specific weight of a fluid is given by the following equation:

$$\gamma = \rho g$$

Therefore, the pressure intensity at a point in a fluid can be written as:

$$P = \gamma h$$

or, in this case,

$$P = wh$$