If three times of the first of the three consecutive odd integers is 3

If three times of the first of the three consecutive odd integers is 3 more than twice the third integer, what is the third integer ?

Answer is Right!

Answer is Wrong!

This question was previously asked in

UPSC CAPF – 2014

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Let the three consecutive odd integers be represented as \(x\), \(x+2\), and \(x+4\), where \(x\) is the first odd integer. The problem states that three times the first integer is 3 more than twice the third integer. We can write this as an equation: \(3x = 2(x+4) + 3\).
Solving the equation:
\(3x = 2x + 8 + 3\)
\(3x = 2x + 11\)
\(3x – 2x = 11\)
\(x = 11\)
The first integer is 11. The three consecutive odd integers are 11, 13, and 15. The third integer is 15.

Consecutive odd integers differ by 2. Setting up the algebraic equation correctly based on the given relationship is crucial to finding the value of the first integer.

We can verify the answer: Three times the first integer (11) is 3 * 11 = 33. Twice the third integer (15) is 2 * 15 = 30. 30 + 3 = 33. The condition is satisfied.

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