The correct answer is $\boxed{\text{C}}$.
The height displacement is given by the following formula:
$$h = \frac{f}{z}d$$
where $h$ is the height displacement, $f$ is the focal length of the camera, $z$ is the flying height, and $d$ is the ground distance from the principal point to the object.
In this case, we have $f = 100 \text{ mm}$, $z = 2000 \text{ m}$, and $d = 4 \text{ cm} = 0.04 \text{ m}$. Substituting these values into the formula, we get:
$$h = \frac{100 \text{ mm}}{2000 \text{ m}} \times 0.04 \text{ m} = 0.02 \text{ m} = 2 \text{ mm}$$
Therefore, the height displacement is 2
89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube