If the current in a capacitor leads the voltage by 80°, the loss angle of the capacitor is

[amp_mcq option1=”10°” option2=”80°” option3=”120°” option4=”170°” correct=”option3″]

The correct answer is $\boxed{\text{B. }80^\circ}$.

The loss angle of a capacitor is the angle between the current and the voltage in a capacitor. It is given by the equation $\tan(\delta) = \frac{R}{X_C}$, where $R$ is the resistance of the capacitor and $X_C$ is the capacitive reactance.

In this case, the current leads the voltage by 80°, so the loss angle is 80°.

Option A is incorrect because it is the angle between the current and the voltage in an inductor.

Option C is incorrect because it is the angle between the current and the voltage in a resistor.

Option D is incorrect because it is the angle between the current and the voltage in a capacitor with a loss angle of 80°.