If the 1st of January of a non-leap year is a Monday, then which one of the following days will the 31st of December of that year be ?
[amp_mcq option1=”Monday” option2=”Tuesday” option3=”Sunday” option4=”None of the above” correct=”option1″]
This question was previously asked in
UPSC CISF-AC-EXE – 2022
A non-leap year has 365 days. To find the day of the week for the 31st of December given the day of the 1st of January, we need to find the number of odd days between these two dates. The number of days from January 1st to December 31st inclusive is 365.
The number of odd days in a given period is the remainder when the total number of days in the period is divided by 7. A non-leap year has 365 days. Dividing 365 by 7 gives a remainder of 1 (365 = 52 * 7 + 1). Therefore, there is 1 odd day in a non-leap year.