118
120
121
119
Answer is Right!
Answer is Wrong!
The correct answer is (a) 118.
There are 100 numbers from 101 to 200. In each of the numbers from 101 to 199, the digit 1 appears once. In the number 200, the digit 1 appears twice. Therefore, the digit 1 appears a total of 100 + 1 – 1 = 118 times.
Option (b) is incorrect because it counts the digit 1 twice in the number 200. Option (c) is incorrect because it counts the digit 1 three times in the number 200. Option (d) is incorrect because it counts the digit 1 four times in the number 200.