If B + D > 2C, B + C = 2D, A + C > B + D and A + D > B + C, the relations between A, B, C and D is

The correct answer is (b).

We can start by combining the first two equations:

$B + D = 2C$
$B + C = 2D$

Subtracting the second equation from the first equation, we get:

$D = C$

We can then substitute this into the third equation:

$A + C > B + D$
$A + C > B + C$

Simplifying, we get:

$A > B$

Finally, we can substitute $C = D$ into the fourth equation:

$A + D > B + C$
$A + D > B + D$

Simplifying, we get:

$A > B$

Therefore, the relations between A, B, C and D is $A > B > D > C$.

Here is a more detailed explanation of each option:

• Option (a): $B > D > C > A$. This is not possible, because $C = D$.
• Option (b): $A > D > C > B$. This is the correct answer, as shown above.
• Option (c): $B > B > D > C$. This is not possible, because $B \neq D$.
• Option (d): $A > B > D > C$. This is not possible, because $A > B$.