If a particle moves with a uniform angular velocity $$\omega $$ radians/sec along the circumference of a circle of radius r, the equation for the velocity of the particle, is A. $${\text{v}} = \omega \sqrt {{{\text{y}}^2} – {{\text{r}}^2}} $$ B. $$\overline {\text{y}} = \omega \sqrt {{\text{y}} – {\text{r}}} $$ C. $${\text{v}} = \omega \sqrt {{{\text{r}}^2} + {{\text{y}}^2}} $$ D. $${\text{v}} = \omega \sqrt {{{\text{r}}^2} – {{\text{y}}^2}} $$

The correct answer is $\boxed{\text{v} = \omega \sqrt{r^2 + y^2}}$.

The velocity of a particle moving in a circle is given by the following equation:

$$\text{v} = \omega r$$

where $\omega$ is the angular velocity and $r$ is the radius of the circle.

In this case, the particle is moving with a uniform angular velocity of $\omega$ radians/sec. The radius of the circle is $r$. Therefore, the velocity of the particle is:

$$\text{v} = \omega r = \omega \sqrt{r^2 + y^2}$$

where $y$ is the distance of the particle from the center of the circle.

Option A is incorrect because it does not include the term $r$. Option B is incorrect because it does not include the term $\omega$. Option C is incorrect because it does not include the term $y$.