Capacity of cell will reduce
Sulphation of plates will occur
Internal resistance will increase
All above will occur
Answer is Right!
Answer is Wrong!
The correct answer is D. All above will occur.
When a lead-acid cell is discharged below 1.8 V, the following will happen:
- The capacity of the cell will reduce. This is because the lead sulfate crystals that form on the plates will grow larger and become more difficult to dissolve.
- Sulphation of plates will occur. This is when lead sulfate crystals form on the plates of the battery. These crystals can build up and eventually block the flow of current, preventing the battery from charging or discharging properly.
- Internal resistance will increase. This is because the lead sulfate crystals that form on the plates create a barrier to the flow of current.
All of these effects can lead to a decrease in the performance of the battery and shorten its lifespan. It is important to avoid discharging a lead-acid battery below 1.8 V if possible. If you do need to discharge the battery below 1.8 V, it is important to recharge it as soon as possible.