If a 6 uF capacitor is charged to 200 V, the charge in coulombs will be

The correct answer is $\boxed{\text{C}}$.

The charge stored in a capacitor is given by the equation $Q = CV$, where $Q$ is the charge in coulombs, $C$ is the capacitance in farads, and $V$ is the voltage in volts. In this case, we are given that $C = 6 \mu F$ and $V = 200 V$. Substituting these values into the equation, we get $Q = (6 \mu F)(200 V) = 1200 \mu C$.

Option A is incorrect because $800 \mu C$ is less than the actual charge. Option B is incorrect because $900 \mu C$ is less than the actual charge. Option D is incorrect because $1600 \mu C$ is greater than the actual charge.