If 5 persons can weave 160 mats in 8 days, how many mats will 8 person

If 5 persons can weave 160 mats in 8 days, how many mats will 8 persons weave in 6 days?

[amp_mcq option1=”200″ option2=”192″ option3=”190″ option4=”180″ correct=”option2″]

This question was previously asked in
UPSC CAPF – 2013
This is a problem involving work and time, often solved using the concept of “Man-Days” or a formula relating work, men, and time.
Let W be the work done (number of mats woven), P be the number of persons, and D be the number of days. We can assume a constant rate of work per person per day.
The total work done is proportional to the number of persons, the number of days, and the individual work rate (R).
$W \propto P \times D \times R$
Assuming the work rate R per person per day is constant for both scenarios, we can write:
$W = k \times P \times D \times R$
Or, more simply, the quantity $W / (P \times D)$ is constant.
$\frac{W_1}{P_1 \times D_1} = \frac{W_2}{P_2 \times D_2}$

In the first case:
$P_1 = 5$ persons
$D_1 = 8$ days
$W_1 = 160$ mats

In the second case:
$P_2 = 8$ persons
$D_2 = 6$ days
$W_2 = ?$ mats

Using the formula:
$\frac{160}{5 \times 8} = \frac{W_2}{8 \times 6}$
$\frac{160}{40} = \frac{W_2}{48}$
$4 = \frac{W_2}{48}$
$W_2 = 4 \times 48$
$W_2 = 192$

So, 8 persons will weave 192 mats in 6 days.

Assuming a constant individual work rate, the total work done is directly proportional to the number of workers and the time they work ($W \propto P \times D$). The relationship can be expressed as $\frac{W_1}{P_1 D_1} = \frac{W_2}{P_2 D_2}$.
This type of problem assumes that all workers work at the same rate and that the work can be divided among them. If the work involves complex coordination or dependencies, this simple formula might not apply.
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