How much packet data rate per user is supported by W-CDMA if the user is stationary?

2.048 Kbps
100 Mbps
2.048 Mbps
1 Gbps

The correct answer is C. 2.048 Mbps.

W-CDMA (Wideband Code Division Multiple Access) is a third-generation (3G) cellular technology that uses a spread spectrum technique called code division multiple access (CDMA) to provide high-speed data and voice services. W-CDMA is a wideband technology, which means that it can support a higher data rate than narrowband technologies such as GSM.

The maximum packet data rate per user supported by W-CDMA is 2.048 Mbps. This means that a single user can transmit or receive data at a rate of up to 2.048 Mbps. This is a very high data rate, and it is sufficient for many applications such as video streaming and web browsing.

The other options are incorrect. Option A is the data rate supported by a 2G GSM system. Option B is the data rate supported by a 4G LTE system. Option D is the data rate supported by a 5G system.

I hope this explanation is helpful. Please let me know if you have any other questions.

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