The correct answer is: C. Not fall below 0.7 V.
The base-emitter voltage (VBE) is the voltage difference between the base and emitter terminals of a transistor. It is a forward-biased voltage, which means that the positive terminal of the voltage source is connected to the base and the negative terminal is connected to the emitter. The minimum value of VBE for a silicon transistor is 0.7 V. If VBE is less than 0.7 V, the transistor will not turn on and will not conduct current.
Option A is incorrect because VBE must be a positive voltage. Option B is incorrect because VBE must be greater than 0.01 V. Option D is incorrect because VBE cannot be between 0 V and 0.1 V.