For a continuous slab of 3 m x 3.5 m size, the minimum overall depth of slab to satisfy vertical deflection limits is A. 50 mm B. 75 mm C. 100 mm D. 120 mm

The correct answer is C. 100 mm.

The minimum overall depth of a slab to satisfy vertical deflection limits is determined by the following equation:

$d = \frac{L^2}{240 f’_c b}$

where:

• $d$ is the minimum overall depth of the slab (in mm)
• $L$ is the clear span of the slab (in mm)
• $f’_c$ is the compressive strength of the concrete (in MPa)
• $b$ is the width of the slab (in mm)

For a continuous slab of 3 m x 3.5 m size, the clear span of the slab is 3 m. Assuming a compressive strength of concrete of 25 MPa and a width of slab of 3.5 m, the minimum overall depth of the slab is:

$d = \frac{3^2}{240 \times 25 \times 3.5} = 100$ mm

Therefore, the minimum overall depth of slab to satisfy vertical deflection limits is 100 mm.

Option A is incorrect because it

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