Find the odd one out of the following items :
EF22, JK42, GH24, VW90, IJ38
EF22
GH24
IJ38
VW90
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC CISF-AC-EXE – 2018
– EF: E is the 5th letter, F is the 6th. 5 + 6 = 11. 11 * 2 = 22. (Matches EF22)
– JK: J is the 10th letter, K is the 11th. 10 + 11 = 21. 21 * 2 = 42. (Matches JK42)
– GH: G is the 7th letter, H is the 8th. 7 + 8 = 15. 15 * 2 = 30. The number given is 24. (Does not match GH24)
– VW: V is the 22nd letter, W is the 23rd. 22 + 23 = 45. 45 * 2 = 90. (Matches VW90)
– IJ: I is the 9th letter, J is the 10th. 9 + 10 = 19. 19 * 2 = 38. (Matches IJ38)
All items except GH24 follow this pattern.