Container I contains a mixture of 2 liters of oil and 3 liters of water. Container II contains a mixture of 6 liters of oil and 7 liters of water. 50% of the mixture of container I and 25% of the mixture of container II are transferred to container III. What is the proportion of oil and water in container III ?
4 : 5
5 : 4
13 : 10
10 : 13
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC CISF-AC-EXE – 2020
– Container II has 6 L oil and 7 L water (total 13 L). 25% of this mixture is transferred, which is 13/4 L = 3.25 L. This 3.25 L contains 25% of the oil from container II (0.25 * 6 L = 1.5 L oil) and 25% of the water from container II (0.25 * 7 L = 1.75 L water).
– Container III receives the transferred amounts. Total oil in container III = 1 L (from I) + 1.5 L (from II) = 2.5 L. Total water in container III = 1.5 L (from I) + 1.75 L (from II) = 3.25 L.
– The proportion of oil to water in container III is 2.5 L : 3.25 L.
– To simplify the ratio, we can multiply both parts by 100 to remove decimals: 250 : 325.
– Dividing both by their greatest common divisor, 25: 250/25 = 10 and 325/25 = 13.
– The ratio is 10 : 13.