Considers a sequence of tossing of a fair coin where the out comes of tosses are independent. The probability of getting the head for the third time in the fifth toss is A. $$\frac{5}{{16}}$$ B. $$\frac{3}{{16}}$$ C. $$\frac{3}{5}$$ D. $$\frac{9}{{16}}$$

$$rac{5}{{16}}$$
$$rac{3}{{16}}$$
$$rac{3}{5}$$
$$rac{9}{{16}}$$

The correct answer is $\boxed{\frac{3}{16}}$.

The probability of getting a head on any given toss of a fair coin is $\frac{1}{2}$. The probability of getting a tail on any given toss of a fair coin is also $\frac{1}{2}$.

The probability of getting a head for the third time in the fifth toss is the probability of getting a tail on the first two tosses, followed by a head on the third toss, followed by a tail on the fourth toss, and finally a head on the fifth toss.

The probability of getting a tail on the first two tosses is $\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$.

The probability of getting a head on the third toss is $\frac{1}{2}$.

The probability of getting a tail on the fourth toss is $\frac{1}{2}$.

The probability of getting a head on the fifth toss is $\frac{1}{2}$.

Therefore, the probability of getting a head for the third time in the fifth toss is $\frac{1}{4} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \boxed{\frac{3}{16}}$.

Option A is incorrect because it is the probability of getting a head on the third toss, regardless of what happens on the first two tosses.

Option B is incorrect because it is the probability of getting a tail on the third toss, regardless of what happens on the first two tosses.

Option C is incorrect because it is the probability of getting a head on the first toss, followed by a tail on the second toss, followed by a head on the third toss.

Option D is incorrect because it is the probability of getting a tail on the first toss, followed by a head on the second toss, followed by a tail on the third toss, followed by a head on the fourth toss.

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