Consider the following sequence : 5, 7, 10, 15, 22, 33, 46, ____, ____

Consider the following sequence :
5, 7, 10, 15, 22, 33, 46, ____, ____
Which one of the alternatives will come at the end of the above sequence ?

61, 79
63, 82
65, 85
59, 71
This question was previously asked in
UPSC CISF-AC-EXE – 2018
The next two numbers in the sequence are 63 and 82.
Let’s find the difference between consecutive terms:
7 – 5 = 2
10 – 7 = 3
15 – 10 = 5
22 – 15 = 7
33 – 22 = 11
46 – 33 = 13
The differences are 2, 3, 5, 7, 11, 13. This sequence of differences is the sequence of prime numbers in ascending order.
The next prime number after 13 is 17.
The term after 46 is 46 + 17 = 63.
The next prime number after 17 is 19.
The term after 63 is 63 + 19 = 82.
The sequence is generated by adding successive prime numbers starting from the first prime number (2) to the previous term.
Term 1: 5
Term 2: 5 + 2 = 7
Term 3: 7 + 3 = 10
Term 4: 10 + 5 = 15
Term 5: 15 + 7 = 22
Term 6: 22 + 11 = 33
Term 7: 33 + 13 = 46
Term 8: 46 + 17 = 63
Term 9: 63 + 19 = 82
The sequence continues: 5, 7, 10, 15, 22, 33, 46, 63, 82.
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