Consider the following electric circuit : [Circuit diagram is present

Consider the following electric circuit :
[Circuit diagram is present in the image]
The current in the above electric circuit is :

1 A
(10/15) A
2 A
1.5 A
This question was previously asked in
UPSC NDA-1 – 2024
The current in the electric circuit is (10/15) A.
The circuit consists of a 10V battery connected to two resistors, 5 ohms and 10 ohms, in series. For resistors connected in series, the total resistance (R_total) is the sum of individual resistances. R_total = 5 Ω + 10 Ω = 15 Ω. According to Ohm’s Law, the current (I) flowing through the circuit is given by V = I * R_total, where V is the voltage. Therefore, I = V / R_total = 10 V / 15 Ω = (10/15) A.
The fraction (10/15) can be simplified to (2/3) A. The options provide the unsimplified fraction (10/15) A as option B. If the resistors were in parallel, the total resistance would be calculated differently (1/R_total = 1/R1 + 1/R2).
Exit mobile version