Signal processing

81. The ROC of z-transform of the discrete time sequence $$x\left( n \right) = {\left( {{1 \over 3}} \right)^n}u\left( n \right) – {\left( {{1 \over 2}} \right)^n}u\left( { – n – 1} \right)$$ is

[amp_mcq option1=”$${1 \over 3} < \left| z \right| < {1 \over 2}$$" option2="$$\left| z \right| > {1 \over 2}$$” option3=”$$\left| z \right| < {1 \over 3}$$" option4="$$2 < \left| z \right| < 3$$" correct="option3"]

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\right)$$ is" class="read-more button" href="https://exam.pscnotes.com/mcq/the-roc-of-z-transform-of-the-discrete-time-sequence-xleft-n-right-left-1-over-3-rightnuleft-n-right-left-1-over-2-rightnuleft-n-1-right/#more-46298">Detailed SolutionThe ROC of z-transform of the discrete time sequence $$x\left( n \right) = {\left( {{1 \over 3}} \right)^n}u\left( n \right) – {\left( {{1 \over 2}} \right)^n}u\left( { – n – 1} \right)$$ is

82. The Fourier series of a real periodic function has only P. Cosine terms if it is even Q. Sine terms if it is even R. Cosine terms if it is odd S. Sine terms if it is odd Which of the above statements are correct?

P and S
P and R
Q and S
Q and R

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above statements are correct?" class="read-more button" href="https://exam.pscnotes.com/mcq/the-fourier-series-of-a-real-periodic-function-has-only-p-cosine-terms-if-it-is-even-q-sine-terms-if-it-is-even-r-cosine-terms-if-it-is-odd-s-sine-terms-if-it-is-odd-which-of-the-above-statements/#more-46235">Detailed SolutionThe Fourier series of a real periodic function has only P. Cosine terms if it is even Q. Sine terms if it is even R. Cosine terms if it is odd S. Sine terms if it is odd Which of the above statements are correct?

83. The region of convergence of z-transform of the sequence $${\left( {{5 \over 6}} \right)^n}u\left( n \right) – {\left( {{6 \over 5}} \right)^n}u\left( { – n – 1} \right)$$ must be

[amp_mcq option1=”$$\left| z \right| < {5 \over 6}$$" option2="$$\left| z \right| > {5 \over 6}$$” option3=”$${5 \over 6} < \left| z \right| < {6 \over 5}$$" option4="$${6 \over 5} < \left| z \right| < \infty $$" correct="option3"]

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the sequence $${\left( {{5 \over 6}} \right)^n}u\left( n \right) – {\left( {{6 \over 5}} \right)^n}u\left( { – n – 1} \right)$$ must be" class="read-more button" href="https://exam.pscnotes.com/mcq/the-region-of-convergence-of-z-transform-of-the-sequence-left-5-over-6-rightnuleft-n-right-left-6-over-5-rightnuleft-n-1-right-must-be/#more-46079">Detailed SolutionThe region of convergence of z-transform of the sequence $${\left( {{5 \over 6}} \right)^n}u\left( n \right) – {\left( {{6 \over 5}} \right)^n}u\left( { – n – 1} \right)$$ must be

84. The impulse response of an LTI system can be obtained by

Differentiating the unit ramp response
Differentiating the unit step response
Integrating the unit ramp response
Integrating the unit step response

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an LTI system can be obtained by" class="read-more button" href="https://exam.pscnotes.com/mcq/the-impulse-response-of-an-lti-system-can-be-obtained-by/#more-46045">Detailed SolutionThe impulse response of an LTI system can be obtained by

85. If $$F\left( s \right) = L\left[ {f\left( t \right)} \right] = {{2\left( {s + 1} \right)} \over {{s^2} + 4s + 7}}$$ then the initial and final values of f(t) are respectively

0, 2
2, 0
$$0,{2 over 7}$$
$${2 over 7},0$$

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{{s^2} + 4s + 7}}$$ then the initial and final values of f(t) are respectively" class="read-more button" href="https://exam.pscnotes.com/mcq/if-fleft-s-right-lleft-fleft-t-right-right-2left-s-1-right-over-s2-4s-7-then-the-initial-and-final-values-of-ft-are-respectively/#more-46029">Detailed SolutionIf $$F\left( s \right) = L\left[ {f\left( t \right)} \right] = {{2\left( {s + 1} \right)} \over {{s^2} + 4s + 7}}$$ then the initial and final values of f(t) are respectively

86. The inverse Laplace transform of the function $${{s + 5} \over {\left( {s + 1} \right)\left( {s + 3} \right)}}$$ is

2e-t - e-3t
2e-t + e-3t
e-t - 2e-3t
e-t + 2e-3t

Detailed SolutionThe inverse Laplace transform of the function $${{s + 5} \over

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{\left( {s + 1} \right)\left( {s + 3} \right)}}$$ is

87. The impulse response and the excitation function of a linear time invariant causal system are shown in figure (a) and (b) respectively. The output of the system at t = 2 sec is equal to

0
$$ rac{1}{2}$$
$$ rac{3}{2}$$
1

Detailed SolutionThe impulse response and the excitation function of a linear time invariant causal system

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are shown in figure (a) and (b) respectively. The output of the system at t = 2 sec is equal to

88. The z-transform of a signal is given by $$C\left( z \right) = {1 \over 4}{{{z^{ – 1}}\left( {1 – {z^{ – 4}}} \right)} \over {{{\left( {1 – {z^{ – 1}}} \right)}^2}}}.$$ Its final value is

$${1 over 4}$$
Zero
1
Infinity

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\right)}^2}}}.$$ Its final value is" class="read-more button" href="https://exam.pscnotes.com/mcq/the-z-transform-of-a-signal-is-given-by-cleft-z-right-1-over-4z-1left-1-z-4-right-over-left-1-z-1-right2-its-final-value-is/#more-45855">Detailed SolutionThe z-transform of a signal
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is given by $$C\left( z \right) = {1 \over 4}{{{z^{ – 1}}\left( {1 – {z^{ – 4}}} \right)} \over {{{\left( {1 – {z^{ – 1}}} \right)}^2}}}.$$ Its final value is

89. The region of convergence of the z-transform of a unit step function is

[amp_mcq option1=”|z| > 1″ option2=”|z| < 1" option3="(Real part of z) > 0″ option4=”(Real part of z) < 0" correct="option2"]

Detailed SolutionThe

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region of convergence of the z-transform of a unit step function is

90. Increased pulse-width in the flat-top sampling, leads to

Attenuation of high frequencies in reproduction
Attenuation of low frequencies in reproduction
Greater aliasing errors in reproduction
No harmful effects in reproduction

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the flat-top sampling, leads to" class="read-more button" href="https://exam.pscnotes.com/mcq/increased-pulse-width-in-the-flat-top-sampling-leads-to/#more-45715">Detailed SolutionIncreased pulse-width in the flat-top sampling, leads to

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