51. {a(n)} is a real-valued periodic sequence with a period N. x(n) and X(k) form N-point Discrete Fourier Transform (DFT) pairs. The DFT Y(k) of the sequence $$y\left( n \right) = \frac{1}{N}\sum\limits_{r = 0}^{N – 1} {x\left( r \right)} x\left( {n + r} \right)$$ is

$${left| {Xleft( k ight)} ight|^2}$$
$$ rac{1}{2}sumlimits_{r = 0}^{N - 1} {Xleft( r ight)X'left( {k + r} ight)} $$
$$ rac{1}{2}sumlimits_{r = 0}^{N - 1} {Xleft( r ight)Xleft( {k + r} ight)} $$
0

Detailed Solution{a(n)} is a real-valued periodic sequence with a period N. x(n) and X(k) form N-point Discrete Fourier Transform (DFT) pairs. The DFT Y(k) of the sequence $$y\left( n

0 576 512"> Subscribe on YouTube
\right) = \frac{1}{N}\sum\limits_{r = 0}^{N – 1} {x\left( r \right)} x\left( {n + r} \right)$$ is

52. For a function g(t), it is given that $$\int\limits_{ – \infty }^{ + \infty } {g\left( t \right){e^{ – j\omega t}}dt = \omega {e^{ – 2{\omega ^2}}}} $$ for any real value $$\omega $$ . If $$y\left( t \right) = \int\limits_{ – \infty }^t {g\left( \tau \right)} d\tau ,\,{\rm{then}}\,\int\limits_{ – \infty }^{ + \infty } {y\left( t \right)} dt$$ is. . . . . . . .

0
#NAME?
$$ - {j over 2}$$
$${j over 2}$$

Detailed SolutionFor a function g(t), it is given that $$\int\limits_{ – \infty }^{ + \infty } {g\left( t \right){e^{ – j\omega

t}}dt = \omega {e^{ – 2{\omega ^2}}}} $$ for any real value $$\omega $$ . If $$y\left( t \right) = \int\limits_{ – \infty }^t {g\left( \tau \right)} d\tau ,\,{\rm{then}}\,\int\limits_{ – \infty }^{ + \infty } {y\left( t \right)} dt$$ is. . . . . . . .

54. Let Y(s) be the unit-step response of a causal system having a transfer function $$G\left( s \right) = {{3 – s} \over {\left( {s + 1} \right)\left( {s + 3} \right)}}$$ That is, $$Y\left( s \right) = {{G\left( s \right)} \over s}.$$ The forced response of the system is

u(t) - 2e-t u(t) + e-3t u(t)
2u(t)
u(t)
2u(t) - 2e-t u(t) + e-3t u(t)

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s} \over {\left( {s + 1} \right)\left( {s + 3} \right)}}$$ That is, $$Y\left( s \right) = {{G\left( s \right)} \over s}.$$ The forced response of the system is" class="read-more button" href="https://exam.pscnotes.com/mcq/let-ys-be-the-unit-step-response-of-a-causal-system-having-a-transfer-function-gleft-s-right-3-s-over-left-s-1-rightleft-s-3-right-that-is-yleft-s-r/#more-51024">Detailed SolutionLet Y(s) be the unit-step response of a causal system having a transfer function $$G\left( s \right) = {{3 – s} \over {\left( {s + 1} \right)\left( {s + 3} \right)}}$$ That is, $$Y\left( s \right) = {{G\left( s \right)} \over s}.$$ The forced response of the system is

55. The Laplace transform of a continuous-time signal x(t) is $$X\left( s \right) = {{5 – s} \over {{s^2} – s – 2}}.$$ If the Fourier transform of this signal exists, then x(t) is

e2tu(t) - 2e-tu(t)
-e2tu(-t) + 2e-tu(t)
-e2tu(-t) - 2e-tu(t)
e2tu(-t) - 2e-tu(t)

Detailed SolutionThe Laplace transform of a continuous-time signal x(t) is $$X\left( s \right) = {{5 – s} \over {{s^2} – s – 2}}.$$

If the Fourier transform of this signal exists, then x(t) is

56. For the discrete-time system shown in the figure, the poles of the system transfer function are located at

2, 3
$$ rac{1}{2},3$$
$$ rac{1}{2}, rac{1}{3}$$
$$2, rac{1}{3}$$

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213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube
are located at" class="read-more button" href="https://exam.pscnotes.com/mcq/for-the-discrete-time-system-shown-in-the-figure-the-poles-of-the-system-transfer-function-are-located-at/#more-50872">Detailed SolutionFor the discrete-time system shown in the figure, the poles of the system transfer function are located at

57. If the region of convergence of x1[n] + x2[n] is $${1 \over 3} < \left| z \right| < {2 \over 3},$$ then the region of convergence of x1[n] - x2[n] includes

”$${1
is $${1 \over 3} < \left| z \right| < {2 \over 3},$$ then the region of convergence of x1[n] - x2[n] includes" class="read-more button" href="https://exam.pscnotes.com/mcq/if-the-region-of-convergence-of-x1n-x2n-is-1-over-3-left-z-right-2-over-3-then-the-region-of-convergence-of-x1n-x2n-includes/#more-50855">Detailed SolutionIf the region of convergence of x1[n] + x2[n] is $${1 \over 3} < \left| z \right| < {2 \over 3},$$ then the region of convergence of x1[n] - x2[n] includes

58. A linear discrete-time system has the characteristics equation, z3 – 0.81 z = 0. The system

Is stable
Is marginally stable
Is unstable
Stability cannot be assessed from the given information

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48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube z3 – 0.81 z = 0. The system" class="read-more button" href="https://exam.pscnotes.com/mcq/a-linear-discrete-time-system-has-the-characteristics-equation-z3-0-81-z-0-the-system/#more-50843">Detailed SolutionA linear discrete-time system has the characteristics equation, z3 – 0.81 z = 0. The system

59. A real-valued signal x(t) limited to the frequency band $$\left| f \right| \le {W \over 2}$$ is passed through a linear time invariant system whose frequency response is $$H\left( f \right) = \left\{ {\matrix{ {{e^{ – j4\pi f,}}} & {\left| f \right| \le {W \over 2}} \cr {0,} & {\left| f \right| > {W \over 2}} \cr } } \right.$$ The output of the system is

x(t + 4)
x(t - 4)
x(t + 2)
x(t - 2)

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288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube \right| \le {W \over 2}} \cr {0,} & {\left| f \right| > {W \over 2}} \cr } } \right.$$ The output of the system is" class="read-more button" href="https://exam.pscnotes.com/mcq/a-real-valued-signal-xt-limited-to-the-frequency-band-left-f-right-le-w-over-2-is-passed-through-a-linear-time-invariant-system-whose-frequency-response-is-hleft-f-right/#more-50197">Detailed SolutionA real-valued signal x(t) limited to the frequency band $$\left| f \right| \le {W \over 2}$$ is passed through a linear time invariant system whose frequency response is $$H\left( f \right) = \left\{ {\matrix{ {{e^{ – j4\pi f,}}} & {\left| f \right| \le {W \over 2}} \cr {0,} & {\left| f \right| > {W \over 2}} \cr } } \right.$$ The output of the system is

60. The z-transform of a system is $$H\left( z \right) = {z \over {z – 0.2}}.$$ If the ROC is |z| < 0.2, then the impulse response of the system is

”(0.2)nu[n
” option2=”(0.2)nu[- n – 1]” option3=”-(0.2)nu[n]” option4=”-(0.2)nu[- n – 1]” correct=”option3″]

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href="https://exam.pscnotes.com/mcq/the-z-transform-of-a-system-is-hleft-z-right-z-over-z-0-2-if-the-roc-is-z-0-2-then-the-impulse-response-of-the-system-is/#more-50006">Detailed SolutionThe z-transform of a system is $$H\left( z \right) = {z \over {z – 0.2}}.$$ If the ROC is |z| < 0.2, then the impulse response of the system is


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