Signal processing

111. Input x(t) and output y(t) of an LTI system are related by the differential equation y”(t) – y'(t) – 6y(t) = x(t). If the system is neither causal nor stable, the impulse response h(t) of the system is

$${1 over 5}{e^{3t}}uleft( { - t} ight) + {1 over 5}{e^{ - 2t}}uleft( { - t} ight)$$
$$ - {1 over 5}{e^{3t}}uleft( { - t} ight) + {1 over 5}{e^{ - 2t}}uleft( { - t} ight)$$
$${1 over 5}{e^{3t}}uleft( { - t} ight) - {1 over 5}{e^{ - 2t}}uleft( t ight)$$
$$ - {1 over 5}{e^{3t}}uleft( { - t} ight) - {1 over 5}{e^{ - 2t}}uleft( t ight)$$

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output y(t) of an LTI system are related by the differential equation y”(t) – y'(t) – 6y(t) = x(t). If the system is neither causal nor stable, the impulse response h(t) of the system is" class="read-more button" href="https://exam.pscnotes.com/mcq/input-xt-and-output-yt-of-an-lti-system-are-related-by-the-differential-equation-yt-yt-6yt-xt-if-the-system-is-neither-causal-nor-stable-the-impulse-response-ht-of-the-system/#more-43184">Detailed SolutionInput x(t) and output y(t) of an LTI system are related by the differential equation y”(t) – y'(t) – 6y(t) = x(t). If the system is neither causal nor stable, the impulse response h(t) of the system is

112. The trigonometric Fourier series of an even function does not have the

Dc term
Cosine terms
Sine terms
Odd harmonic terms

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6.3-42 24.9-48.3 48.6-11.4 42.9-11.4 132.3-11.4 132.3s0 89.4 11.4 132.3c6.3 23.7 24.8 41.5 48.3 47.8C117.2 448 288 448 288 448s170.8 0 213.4-11.5c23.5-6.3 42-24.2 48.3-47.8 11.4-42.9 11.4-132.3 11.4-132.3s0-89.4-11.4-132.3zm-317.5 213.5V175.2l142.7 81.2-142.7 81.2z"/> Subscribe on YouTube
button" href="https://exam.pscnotes.com/mcq/the-trigonometric-fourier-series-of-an-even-function-does-not-have-the/#more-43102">Detailed SolutionThe trigonometric Fourier series of an even function does not have the

113. Consider the sequence x[n] = {-4 – j5, 1 + j2, 4} The conjugate antisymmetric part of the sequence is

{-4 - j2.5, j2, 4 - j2.5}
{-j2.5, 1, j2.5}
{-j5, j2, 0}
{-4, 1, 4}

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the sequence x[n] = {-4 – j5, 1 + j2, 4} The conjugate antisymmetric part of the sequence is" class="read-more button" href="https://exam.pscnotes.com/mcq/consider-the-sequence-xn-4-j5-1-j2-4-the-conjugate-antisymmetric-part-of-the-sequence-is/#more-42988">Detailed SolutionConsider the sequence x[n] = {-4 – j5, 1 + j2, 4} The conjugate antisymmetric part of the sequence is

114. Given that F(s) is the one-sided Laplace transform of f(t), the Laplace transform of $$\int\limits_0^t {f\left( \tau \right)} d\tau $$ is

”sF(s)
”$${1
”$$intlimits_0^s
”$${1
$$” correct=”option4″]

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class="youtube-subscribe-container"> Subscribe on YouTube is the one-sided Laplace transform of f(t), the Laplace transform of $$\int\limits_0^t {f\left( \tau \right)} d\tau $$ is" class="read-more button" href="https://exam.pscnotes.com/mcq/given-that-fs-is-the-one-sided-laplace-transform-of-ft-the-laplace-transform-of-intlimits_0t-fleft-tau-right-dtau-is/#more-42881">Detailed SolutionGiven that F(s) is the one-sided Laplace transform of f(t), the Laplace transform of $$\int\limits_0^t {f\left( \tau \right)} d\tau $$ is

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