Irrigation engineering

1. Solution of Laplacian equation in three dimensions $$\frac{{{{\text{d}}^2}\varphi }}{{{\text{d}}{{\text{x}}^2}}} + \frac{{{{\text{d}}^2}\varphi }}{{{\text{d}}{{\text{y}}^2}}} + \frac{{{{\text{d}}^2}\varphi }}{{{\text{d}}{{\text{z}}^2}}} = 0$$ of water in a syphon, is done by A. Analytical method B. Khosla’s method C. Method of relaxation D. Unwin’s method

Analytical method
Khosla's method
Method of relaxation
Unwin's method

Detailed SolutionSolution of Laplacian equation in three dimensions $$\frac{{{{\text{d}}^2}\varphi }}{{{\text{d}}{{\text{x}}^2}}} + \frac{{{{\text{d}}^2}\varphi }}{{{\text{d}}{{\text{y}}^2}}} + \frac{{{{\text{d}}^2}\varphi }}{{{\text{d}}{{\text{z}}^2}}} = 0$$ of water in a syphon, is done by A. Analytical method B. Khosla’s method C. Method of relaxation D. Unwin’s method

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2. The maximum rainfall depth of 300 mm in 24 hours has a return period of 100 years. The probability of 24 hours rainfall equal to or greater than 300 mm occurring at least once in 10 years is given by A. 0.9910 B. 1 – 0.9910 C. 0.9100 D. 1 – 0.9100

0.991
1 - 0.9910
0.91
1 - 0.9100

Detailed SolutionThe maximum rainfall depth of 300 mm in 24 hours has a return period of 100 years. The probability of 24 hours rainfall equal to or greater than 300 mm occurring at least once in 10 years is given by A. 0.9910 B. 1 – 0.9910 C. 0.9100 D. 1 – 0.9100

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3. The peak of a 4 hour flood hydrograph is 240 m3/sec . If the rainfall excess is 80 mm and base flow which is constant is 40 m3/sec, then the peak of 4-hours unit hydrograph will be A. 20 m3/sec B. 25 m3/sec C. 30 m3/sec D. 35 m3/sec

20 m3/sec
25 m3/sec
30 m3/sec
35 m3/sec

Detailed SolutionThe peak of a 4 hour flood hydrograph is 240 m3/sec . If the rainfall excess is 80 mm and base flow which is constant is 40 m3/sec, then the peak of 4-hours unit hydrograph will be A. 20 m3/sec B. 25 m3/sec C. 30 m3/sec D. 35 m3/sec

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4. Fundamental momentum equation for a hydraulic jump, is A. $${\text{D}}_1^2 – {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} – {{\text{V}}_2}} \right)$$ B. $${\text{D}}_2^2 – {\text{D}}_1^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} – {{\text{V}}_2}} \right)$$ C. $${\text{D}}_1^2 – {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} – {{\text{V}}_1}} \right)$$ D. $${\text{D}}_1^2 + {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} – {{\text{V}}_1}} \right)$$

$${ ext{D}}_1^2 - { ext{D}}_2^2 = rac{{2{ ext{q}}}}{{ ext{g}}}left( {{{ ext{V}}_1} - {{ ext{V}}_2}} ight)$$
$${ ext{D}}_2^2 - { ext{D}}_1^2 = rac{{2{ ext{q}}}}{{ ext{g}}}left( {{{ ext{V}}_1} - {{ ext{V}}_2}} ight)$$
$${ ext{D}}_1^2 - { ext{D}}_2^2 = rac{{2{ ext{q}}}}{{ ext{g}}}left( {{{ ext{V}}_2} - {{ ext{V}}_1}} ight)$$
$${ ext{D}}_1^2 + { ext{D}}_2^2 = rac{{2{ ext{q}}}}{{ ext{g}}}left( {{{ ext{V}}_2} - {{ ext{V}}_1}} ight)$$

Detailed SolutionFundamental momentum equation for a hydraulic jump, is A. $${\text{D}}_1^2 – {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} – {{\text{V}}_2}} \right)$$ B. $${\text{D}}_2^2 – {\text{D}}_1^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_1} – {{\text{V}}_2}} \right)$$ C. $${\text{D}}_1^2 – {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} – {{\text{V}}_1}} \right)$$ D. $${\text{D}}_1^2 + {\text{D}}_2^2 = \frac{{2{\text{q}}}}{{\text{g}}}\left( {{{\text{V}}_2} – {{\text{V}}_1}} \right)$$

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5. The field capacity of a soil is 25%, its permanent wilting point is 15% and specific dry unity weight is 1.5. If the depth of root zone of a crop, is 80 cm, the storage capacity of the soil, is A. 8 cm B. 10 cm C. 12 cm D. 14 cm

8 cm
10 cm
12 cm
14 cm

Detailed SolutionThe field capacity of a soil is 25%, its permanent wilting point is 15% and specific dry unity weight is 1.5. If the depth of root zone of a crop, is 80 cm, the storage capacity of the soil, is A. 8 cm B. 10 cm C. 12 cm D. 14 cm

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6. When the reservoir is full, the maximum compressive force in a gravity dam is produced A. at the toe B. at the heel C. within the middle third of base D. at centre of base

at the toe
at the heel
within the middle third of base
at centre of base

Detailed SolutionWhen the reservoir is full, the maximum compressive force in a gravity dam is produced A. at the toe B. at the heel C. within the middle third of base D. at centre of base

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7. A land is known as waterlogged A. when the permanent wilting point is reached B. when gravity drainage has ceased C. capillary fringe reaches the root zone of plants D. none of the above

when the permanent wilting point is reached
when gravity drainage has ceased
capillary fringe reaches the root zone of plants
none of the above

Detailed SolutionA land is known as waterlogged A. when the permanent wilting point is reached B. when gravity drainage has ceased C. capillary fringe reaches the root zone of plants D. none of the above

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8. A river training work is generally required when the river is A. aggrading type B. degrading type C. meandering type D. both (A) and (B)

aggrading type
degrading type
meandering type
both (A) and (B)

Detailed SolutionA river training work is generally required when the river is A. aggrading type B. degrading type C. meandering type D. both (A) and (B)

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9. A river training work is generally required when the river is A. Meandering B. Aggrading C. Degrading D. All the above

Meandering
Aggrading
Degrading
All the above

Detailed SolutionA river training work is generally required when the river is A. Meandering B. Aggrading C. Degrading D. All the above

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10. According to Bligh’s creep theory, percolating water flows along A. Straight path under the foundation of the dam B. Circular path under the foundation of the dam C. The outline of the base of the foundation of the dam D. None of these

Straight path under the foundation of the dam
Circular path under the foundation of the dam
The outline of the base of the foundation of the dam
None of these

Detailed SolutionAccording to Bligh’s creep theory, percolating water flows along A. Straight path under the foundation of the dam B. Circular path under the foundation of the dam C. The outline of the base of the foundation of the dam D. None of these

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