The correct answer is: A. Resistive.
At very low frequencies, the reactance of the capacitor is very small compared to the resistance of the resistor. This means that the current through the circuit is almost entirely due to the resistor, and the voltage across the capacitor is negligible. As a result, the circuit behaves almost purely resistive.
The reactance of a capacitor is given by the following equation:
$X_C = \frac{1}{2\pi fC}$
where $f$ is the frequency and $C$ is the capacitance. At very low frequencies, $f$ is small, so $X_C$ is also small.
The resistance of a resistor is given by the following equation:
$R = \rho \frac{l}{A}$
where $\rho$ is the resistivity of the material, $l$ is the length of the resistor, and $A$ is the cross-sectional area of the resistor. The resistance of a resistor is independent of frequency.
Therefore, at very low frequencies, the reactance of the capacitor is much smaller than the resistance of the resistor. This means that the current through the circuit is almost entirely due to the resistor, and the voltage across the capacitor is negligible. As a result, the circuit behaves almost purely resistive.