Assuming human normal vision distance 25 cm, smallest measurable angle 20″, and intraocular distance 6.5 cm, the smallest depth to be discerned is A. 0.1 mm B. 0.5 mm C. 1.00 mm D. 1.1 mm

0.1 mm
0.5 mm
1.00 mm
1.1 mm

The correct answer is $\boxed{\text{C}}$.

The smallest depth that can be discerned by the human eye is given by the formula:

$$d = \frac{2 \tan \theta}{f}$$

where $d$ is the depth, $\theta$ is the smallest measurable angle, and $f$ is the focal length of the eye.

The smallest measurable angle is 20 arcminutes, which is equal to $\frac{1}{3600} \pi$ radians. The focal length of the eye is approximately 6.5 cm.

Substituting these values into the formula, we get:

$$d = \frac{2 \tan \left( \frac{1}{3600} \pi \right)}{0.065} = 1.00 \text{ mm}$$

Therefore, the smallest depth that can be discerned by the human eye is 1.00 mm.

Option A is incorrect because it is half the correct value. Option B is incorrect because it is twice the correct value. Option D is incorrect because it is greater than the correct value.