An odd shaped body weighing 7.5 kg and occupying 0.01 m3 volume will be completely submerged in a fluid having specific gravity of A. 1 B. 1.2 C. 0.8 D. 0.75

1
1.2
0.8
0.75

The correct answer is A.

Specific gravity is the ratio of the density of a substance to the density of a reference substance. The reference substance is usually water, which has a specific gravity of 1.

The density of a substance is its mass per unit volume. The mass of the odd shaped body is 7.5 kg and its volume is 0.01 m3. Therefore, the density of the odd shaped body is 750 kg/m3.

The specific gravity of the fluid is 1.2. This means that the density of the fluid is 1.2 times the density of water. Therefore, the density of the fluid is 1.2 x 1000 kg/m3 = 1200 kg/m3.

The odd shaped body will be completely submerged in the fluid because the density of the body is less than the density of the fluid.

Option B is incorrect because the specific gravity of the fluid is 1.2, which is greater than the density of the body. Therefore, the body will float in the fluid.

Option C is incorrect because the specific gravity of the fluid is 0.8, which is less than the density of the body. Therefore, the body will sink in the fluid.

Option D is incorrect because the specific gravity of the fluid is 0.75, which is less than the density of the body. Therefore, the body will sink in the fluid.