An object weighs 9 N on the surface of the Earth. What would be its we

An object weighs 9 N on the surface of the Earth. What would be its weight, when measured on the surface of a planet where the acceleration due to gravity is 9 times that on the Earth ?

The weight would remain the same
The weight would be equal to 1 N
The weight would become 9 times
The weight will be reduced to $rac{1}{9}$ N
This question was previously asked in
UPSC CDS-1 – 2022
The weight would become 9 times.
Weight is defined as the force of gravity acting on an object, given by the formula W = m * g, where W is weight, m is mass, and g is the acceleration due to gravity. The mass of the object remains constant regardless of location. If the acceleration due to gravity (g) on the planet is 9 times that on Earth (g_planet = 9 * g_earth), then the weight on the planet will be W_planet = m * g_planet = m * (9 * g_earth) = 9 * (m * g_earth) = 9 * W_earth. Thus, the weight on the planet becomes 9 times the weight on Earth.
The initial weight on Earth is 9 N. The new weight on the planet would be 9 * 9 N = 81 N. Option C accurately states the relationship between the new weight and the original weight.
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