An object of mass 2000 g possesses 100 J kinetic energy. The object must be moving with a speed of
10.0 m/s
11.1 m/s
11.2 m/s
12.1 m/s
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC NDA-2 – 2021
The correct option is A. The kinetic energy (KE) of an object is given by the formula $\text{KE} = \frac{1}{2}mv^2$, where $m$ is the mass and $v$ is the speed. Given $\text{KE} = 100 \, \text{J}$ and $m = 2000 \, \text{g} = 2 \, \text{kg}$, we can solve for $v$.
Substitute the given values into the kinetic energy formula: $100 \, \text{J} = \frac{1}{2} \times (2 \, \text{kg}) \times v^2$. This simplifies to $100 = 1 \times v^2$, so $v^2 = 100$. Taking the square root of both sides gives $v = 10 \, \text{m/s}$ (since speed is a magnitude and must be non-negative).