An electrical circuit having combinations of resistances and capacitance is given below. The current, flowing through the circuit will be
1 A
2 A
1·5 A
0·5 A
Answer is Right!
Answer is Wrong!
This question was previously asked in
UPSC CDS-2 – 2022
– The parallel combination consists of two branches: one with the 20 ohm resistor and the capacitor in series, and another branch which appears to be a simple wire (zero resistance).
– In steady state DC, the capacitor acts as an open circuit, meaning the branch containing the 20 ohm resistor and capacitor has effectively infinite resistance to DC current flow.
– The other branch in parallel has zero resistance (a wire).
– Current always follows the path of least resistance. In parallel, a zero-resistance path effectively shorts out any parallel path with resistance. Thus, all the current passing through the 10 ohm resistor will flow through the wire branch, and no current will flow through the branch containing the 20 ohm resistor and capacitor in steady state.
– The equivalent resistance of the parallel combination is 0 ohms.
– The total resistance of the circuit is the sum of the series resistor and the equivalent parallel resistance: R_total = 10 ohms + 0 ohms = 10 ohms.
– The total current flowing from the battery is given by Ohm’s Law: I = V / R_total = 10V / 10 ohms = 1 A. This is the current flowing through the circuit from the battery.