An electric refrigerator rated 400 W operates 10 hours/day. What is th

An electric refrigerator rated 400 W operates 10 hours/day. What is the cost of the energy to operate it for 30 days at ₹ 3.00 per kWh?

₹ 360

₹ 3,600

₹ 36

₹ 400

Answer is Right!

Answer is Wrong!

This question was previously asked in

UPSC CISF-AC-EXE – 2020

Download PDF Attempt Online

The power rating of the refrigerator is 400 W, which is equal to 0.4 kW (since 1 kW = 1000 W). The refrigerator operates for 10 hours per day. Over 30 days, the total operation time is 10 hours/day * 30 days = 300 hours. The total energy consumed is the power multiplied by the time: Energy (kWh) = Power (kW) * Time (hours) = 0.4 kW * 300 hours = 120 kWh. The cost of energy is ₹ 3.00 per kWh. Total cost = Energy consumed * Cost per kWh = 120 kWh * ₹ 3.00/kWh = ₹ 360.

Energy consumed is calculated as Power (in kW) multiplied by Time (in hours). The total cost is the energy consumed multiplied by the rate per unit of energy (kWh).

The unit of energy used for billing is typically the kilowatt-hour (kWh), often called a ‘unit’ of electricity. Power in watts needs to be converted to kilowatts before calculating energy in kWh if time is in hours.

Join Our Telegram Channel

More similar MCQ questions for Exam preparation:-