An electric bulb is connected to a 110 V generator. The current is 0.2

An electric bulb is connected to a 110 V generator. The current is 0.2 A. What is the power of the bulb ?

[amp_mcq option1=”0.22 W” option2=”2.2 W” option3=”22 W” option4=”220 W” correct=”option3″]

This question was previously asked in

UPSC CDS-2 – 2021

The power (P) of an electrical device is given by the product of the voltage (V) across it and the current (I) flowing through it. Given V = 110 V and I = 0.2 A, the power is P = V × I = 110 V × 0.2 A = 22 Watts.

Electrical power (P) is calculated using the formula P = VI, where V is the voltage in volts and I is the current in amperes. The unit of power is the Watt (W).

Other useful formulas relating power, voltage, current, and resistance (R) are P = I²R and P = V²/R (derived from Ohm’s Law, V=IR). In this problem, only voltage and current were given, so P=VI is the direct formula to use.

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