An electric bulb is connected to 220 V generator. The current drawn is

An electric bulb is connected to 220 V generator. The current drawn is 600 mA. What is the power of the bulb?

132 W
13.2 W
1320 W
13200 W
This question was previously asked in
UPSC NDA-2 – 2022
The power (P) of an electrical device connected to a circuit is given by the formula:
P = V × I
Where V is the voltage across the device and I is the current flowing through it.
Given:
Voltage (V) = 220 V
Current (I) = 600 mA
First, convert the current from milliamperes (mA) to amperes (A):
1 A = 1000 mA
So, 600 mA = 600 / 1000 A = 0.6 A.
Now, calculate the power:
P = 220 V × 0.6 A
P = 220 × (6/10) W
P = 22 × 6 W
P = 132 W.
Power is calculated as the product of voltage and current (P=VI). Ensure units are in Volts and Amperes to get Power in Watts.
This calculation is a fundamental application of Ohm’s law and the power formula in basic electricity. The resistance of the bulb could also be calculated using Ohm’s law (V=IR), but it is not needed to find the power. The power rating (in Watts) indicates the rate at which the bulb consumes electrical energy.
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