An electric bulb is connected to 220 V generator. The current drawn is 600 mA. What is the power of the bulb?
[amp_mcq option1=”132 W” option2=”13.2 W” option3=”1320 W” option4=”13200 W” correct=”option1″]
This question was previously asked in
UPSC NDA-2 – 2022
P = V × I
Where V is the voltage across the device and I is the current flowing through it.
Given:
Voltage (V) = 220 V
Current (I) = 600 mA
First, convert the current from milliamperes (mA) to amperes (A):
1 A = 1000 mA
So, 600 mA = 600 / 1000 A = 0.6 A.
Now, calculate the power:
P = 220 V × 0.6 A
P = 220 × (6/10) W
P = 22 × 6 W
P = 132 W.