Among the following compounds, the one that undergoes de-protonation most readily in the presence of base to form a carbanion is A. B. C. D.

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The correct answer is A.

The compound in option A is a primary alkyl halide, which is the most reactive type of alkyl halide towards deprotonation. This is because the carbon atom in the alkyl halide is bonded to three other atoms, which makes it electron-deficient. When a base is added to the compound, the base will abstract a proton from the carbon atom, forming a carbanion. The carbanion is an anion with a negative charge on a carbon atom. Carbanions are very reactive species and will react with a variety of other compounds.

The compounds in options B, C, and D are all secondary and tertiary alkyl halides. Secondary and tertiary alkyl halides are less reactive towards deprotonation than primary alkyl halides. This is because the carbon atom in the alkyl halide is bonded to two and one other atoms, respectively, which makes it less electron-deficient.

In conclusion, the compound in option A is the most reactive towards deprotonation because it is a primary alkyl halide.

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