A train with a length of 335 m is travelling at a speed of 90 km/h. What is the time taken by the train to pass a 290 m long platform?
[amp_mcq option1=”25 s” option2=”23 s” option3=”20 s” option4=”30 s” correct=”option1″]
This question was previously asked in
UPSC CISF-AC-EXE – 2024
Total distance to be covered = Length of train + Length of platform.
Total distance = 335 m + 290 m = 625 m.
The speed of the train is given in km/h, so we need to convert it to m/s to be consistent with the distance unit (meters) and time unit (seconds).
Speed = 90 km/h.
To convert km/h to m/s, multiply by the factor (1000 m / 3600 s) = 5/18.
Speed in m/s = 90 * (5/18) m/s = (90/18) * 5 m/s = 5 * 5 m/s = 25 m/s.
The time taken is calculated using the formula: Time = Distance / Speed.
Time = 625 m / 25 m/s.
Time = 25 seconds.