A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?

8
24
30
16

The correct answer is (d) 16.

If the student got twice as many sums wrong as he got right, then he got 2x wrong and x right. Since he attempted 48 sums in all, then x + 2x = 48. Solving for x, we get x = 16. Therefore, the student got 16 sums right.

Option (a) is incorrect because it is the number of sums that the student got wrong. Option (b) is incorrect because it is the total number of sums that the student attempted. Option (c) is incorrect because it is the sum of the number of sums that the student got right and the number of sums that he got wrong.

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